Bucktown, Indiana

Bucktown
Unincorporated community

Sullivan County's location in Indiana
Bucktown

Location in Sullivan County, Indiana

Coordinates: 38°59′41″N 87°15′36″W / 38.99472°N 87.26000°W / 38.99472; -87.26000Coordinates: 38°59′41″N 87°15′36″W / 38.99472°N 87.26000°W / 38.99472; -87.26000
Country United States
State Indiana
County Sullivan
Township Jefferson
Elevation[1] 594 ft (181 m)
Time zone Eastern (EST)
ZIP code 47838
Area code(s) 812
GNIS feature ID 431756

Bucktown is an unincorporated community in Jefferson Township, Sullivan County, in the U.S. state of Indiana.[2]

The community is part of the Terre Haute Metropolitan Statistical Area.

Geography

Bucktown is located at 38°59′41″N 87°15′36″W / 38.99472°N 87.26000°W / 38.99472; -87.26000.

References

  1. "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved 2016-08-29.
  2. "Bucktown, Indiana". Geographic Names Information System. United States Geological Survey. Retrieved 2010-08-18.


This article is issued from Wikipedia - version of the 8/29/2016. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.