De Soto, Nebraska
De Soto, Nebraska | |
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Coordinates: 41°30′4.15″N 96°3′24.15″W / 41.5011528°N 96.0567083°WCoordinates: 41°30′4.15″N 96°3′24.15″W / 41.5011528°N 96.0567083°W | |
Country | United States |
State | Nebraska |
County | Washington |
Elevation | 1,007 ft (307 m) |
Time zone | Central (CST) (UTC-6) |
• Summer (DST) | CDT (UTC-5) |
Area code(s) | 402 |
De Soto is an unincorporated community in Washington County, Nebraska, United States.[1] It was named in honor of the sixteenth-century Spanish explorer, Hernando De Soto.[2] De Soto was founded in 1855 and served as the county seat from 1858-1866. During its heyday, the town hosted many flourishing new businesses: hotels, saloons, stores, newspapers and banks.[3]
De Soto contains farmland with about three families residing there.[4]
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