Jacksonburg, West Virginia
Jacksonburg | |
---|---|
Census-designated place (CDP) | |
Jacksonburg Location within the state of West Virginia | |
Coordinates: 39°31′56″N 80°38′30″W / 39.53222°N 80.64167°WCoordinates: 39°31′56″N 80°38′30″W / 39.53222°N 80.64167°W | |
Country | United States |
State | West Virginia |
County | Wetzel |
Area[1] | |
• Total | 1.501 sq mi (3.89 km2) |
• Land | 1.481 sq mi (3.84 km2) |
• Water | 0.020 sq mi (0.05 km2) |
Population (2010)[2] | |
• Total | 182 |
• Density | 120/sq mi (47/km2) |
Time zone | Eastern (EST) (UTC-5) |
• Summer (DST) | EDT (UTC-4) |
Jacksonburg is a census-designated place (CDP) in Wetzel County, West Virginia, United States. It lies at an elevation of 748 feet (228 m).[3] As of the 2010 census, its population was 182.[2]
References
- ↑ "US Gazetteer files: 2010, 2000, and 1990". United States Census Bureau. 2011-02-12. Retrieved 2011-04-23.
- 1 2 "American FactFinder". United States Census Bureau. Archived from the original on September 11, 2013. Retrieved 2011-05-14.
- ↑ U.S. Geological Survey Geographic Names Information System: Jacksonburg, West Virginia
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