San Francisco Huehuetlán
| San Francisco Huehuetlán | |
|---|---|
| Municipality and town | |
  San Francisco Huehuetlán Location in Mexico | |
| Coordinates: 18°12′N 96°57′W / 18.200°N 96.950°WCoordinates: 18°12′N 96°57′W / 18.200°N 96.950°W | |
| Country |
 Mexico |
| State | Oaxaca |
| Area | |
| • Total | 15.31 km2 (5.91 sq mi) |
| Population (2005) | |
| • Total | 1,251 |
| Time zone | Central Standard Time (UTC-6) |
| • Summer (DST) | Central Daylight Time (UTC-5) |
San Francisco Huehuetlán is a town and municipality in Oaxaca in south-western Mexico. The municipality covers an area of 15.31 km². It is part of the Teotitlán District in the north of the Cañada Region.
As of 2005, the municipality had a total population of 1251.[1]
References
- ↑ "San Francisco Huehuetlán". Enciclopedia de los Municipios de México. Instituto Nacional para el Federalismo y el Desarrollo Municipal. Retrieved June 12, 2009.
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