United States presidential election in Maryland, 1988

United States presidential election in Maryland, 1988

November 8, 1988

Nominee George H. W. Bush Michael Dukakis Party Republican Democratic Home state Texas Massachusetts Running mate Dan Quayle Lloyd Bentsen Electoral vote 10 0 Popular vote 876,167 826,304 Percentage 51.11% 48.20%

County Results   Dukakis—70-80%   Dukakis—60-70%   Dukakis—50-60%   Bush—50-60%   Bush—60-70%   Bush—70-80%

President before election Ronald Reagan Republican Elected President George H.W. Bush Republican

Elections in Maryland
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The 1988 United States presidential election in Maryland took place on November 8, 1988, as part of the 1988 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for President and Vice President.

Maryland was won by Vice President George H.W. Bush (R-Texas), with 51.11% of the popular vote, over Massachusetts Governor Mike Dukakis (D-Massachusetts) with 48.20% of the popular vote.^[1] Bush ultimately won the national vote, defeating Governor Dukakis.^[2]

Results

References

State Results of the 1988 U.S. presidential election
Candidates	Michael Dukakis George H. W. Bush Ron Paul Lenora Fulani Full list
General articles	Election timeline Democratic primaries Republican primaries Republican Convention Democratic Convention Debates
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Other 1988 elections	House Senate Gubernatorial